echo 흉내내기 - command argument 활용 코드 구현

#include <stdio.h>

/* echo command-line arguments; 1st version */

main(int argc, char *argv[])

{

int i;

for(i=1;i<argc;i++)

printf("%s%s",argv[i],(i<argc-1)?" ":"");

printf("\n");

return 0;

}

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pointer 사용

main(int argc, char *argv[])

{

while(argc-->0)

printf("%s%s",*++argv,(argc>1)?" ":"");

printf("\n");

return 0;

}